What are the solutions to the equation 4x^2-19x+24=0 ?

The solutions to the equation 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8

Find the zeros of 4x^2-19x+24=0

The zeros of 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8

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4 x^{2} - 19 x + 24 = 0

x = \frac{19}{8} + i \frac{23}{8}, x = \frac{19}{8} - i \frac{23}{8}

Solution steps

4 x^{2} - 19 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 4 \cdot 24}{2 \cdot 4}

Simplify

(- 19)^{2} - 4 \cdot 4 \cdot 24 : 23 i

x_{1, 2} = \frac{- ( - 19 ) \pm 23 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 23 i}{2 \cdot 4}, x_{2} = \frac{- ( - 19 ) - 23 i}{2 \cdot 4}

x = \frac{- ( - 19 ) + 23 i}{2 \cdot 4} : \frac{19}{8} + i \frac{23}{8}

x = \frac{- ( - 19 ) - 23 i}{2 \cdot 4} : \frac{19}{8} - i \frac{23}{8}

The solutions to the quadratic equation are:

x = \frac{19}{8} + i \frac{23}{8}, x = \frac{19}{8} - i \frac{23}{8}

7 x^{2} + 20 x - 3

\frac{3 3}{3}

16 x^{2} - 40 x y + 25 y^{2}

10 x^{2} - 25 = 0

What are the solutions to the equation 4x^2-19x+24=0 ?
The solutions to the equation 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8
Find the zeros of 4x^2-19x+24=0
The zeros of 4x^2-19x+24=0 are x= 19/8+i(sqrt(23))/8 ,x= 19/8-i(sqrt(23))/8