What is the answer to (x-4)/3-(x-5)/2 =-(x-7) ?

The answer to (x-4)/3-(x-5)/2 =-(x-7) is x=7

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(x-4)/3-(x-5)/2 =-(x-7)

\frac{x - 4}{3} - \frac{x - 5}{2} = - (x - 7)

x = 7

Solution steps

\frac{x - 4}{3} - \frac{x - 5}{2} = - (x - 7)

Multiply by LCM

2 (x - 4) - 3 (x - 5) = - 6 (x - 7)

Expand

2 (x - 4) - 3 (x - 5) : - x + 7

Expand

- 6 (x - 7) : - 6 x + 42

- x + 7 = - 6 x + 42

Move

7

to the right side

- x = - 6 x + 35

Move

6 x

to the left side

5 x = 35

Divide both sides by

5

x = 7

D, \frac{D}{F + 2 n ^{2}} = q

- 2 - 3 (2 x + 9) = - 32

\frac{3}{8} x + \frac{1}{6} x + \frac{5}{12} x = 69

- 2 (7 x) = - 28

\frac{4 x + 2}{3} - \frac{5 x - 7}{6} = \frac{3 - x}{2}

What is the answer to (x-4)/3-(x-5)/2 =-(x-7) ?
The answer to (x-4)/3-(x-5)/2 =-(x-7) is x=7
Solve for x: (x-4)/3-(x-5)/2 =-(x-7)
The solution is x=7