What is the answer to (x+4)(x+1)=(x+2)^2 ?

The answer to (x+4)(x+1)=(x+2)^2 is x=0

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(x+4)(x+1)=(x+2)^2

(x + 4) (x + 1) = (x + 2)^{2}

x = 0

Solution steps

(x + 4) (x + 1) = (x + 2)^{2}

Expand

(x + 4) (x + 1) : x^{2} + 5 x + 4

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

x^{2} + 5 x + 4 = x^{2} + 4 x + 4

Move

4

to the right side

x^{2} + 5 x = x^{2} + 4 x

Subtract

x^{2} + 4 x

from both sides

x^{2} + 5 x - (x^{2} + 4 x) = x^{2} + 4 x - (x^{2} + 4 x)

Simplify

x = 0

3 (2 x + 7) = 6 (x + 4) - 3

- (4 - x) (x + 3) = x^{2} - 40

\frac{- 8 x - 1}{3} + 1.5 = - 9.5

x, 10 x + 5 y = 5

\frac{2}{3} (1 + x) = a

What is the answer to (x+4)(x+1)=(x+2)^2 ?
The answer to (x+4)(x+1)=(x+2)^2 is x=0
Solve for x: (x+4)(x+1)=(x+2)^2
The solution is x=0