What is the answer to (x+a)(x+b)=x^2+(a+b)x+ab ?

The answer to (x+a)(x+b)=x^2+(a+b)x+ab is True for all x

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(x+a)(x+b)=x^2+(a+b)x+ab

(x + a) (x + b) = x^{2} + (a + b) x + ab

True for all x

Solution steps

(x + a) (x + b) = x^{2} + (a + b) x + ab

Expand

(x + a) (x + b) : x^{2} + b x + a x + ab

Expand

x^{2} + (a + b) x + ab : x^{2} + a x + b x + ab

x^{2} + b x + a x + ab = x^{2} + a x + b x + ab

Move

ab

to the right side

x^{2} + b x + a x = x^{2} + a x + b x

Subtract

x^{2} + a x + b x

from both sides

x^{2} + b x + a x - (x^{2} + a x + b x) = x^{2} + a x + b x - (x^{2} + a x + b x)

Simplify

0 = 0

Both sides are equal

True for all x

t, t (x) = 3 x

x, y + 4 x + 3 = 0

y = 4 (- 2) + 3

x, y - 1 = \frac{2}{3} (x - 3)

6 x + 15 - 8 - 8 x = 7

What is the answer to (x+a)(x+b)=x^2+(a+b)x+ab ?
The answer to (x+a)(x+b)=x^2+(a+b)x+ab is True for all x