What is the answer to -2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4) ?

The answer to -2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4) is y=4

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-2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4)

- 2 y - 3 - (- 4) y + 5 + [- y + 2 - (3 y - 1) + 2 y - 5] = - (y - 4)

y = 4

Solution steps

- 2 y - 3 - (- 4) y + 5 + [- y + 2 - (3 y - 1) + 2 y - 5] = - (y - 4)

Remove parentheses:

(- a) = - a, - (- a) = a

- 2 y - 3 + 4 y + 5 - y + 2 - (3 y - 1) + 2 y - 5 = - (y - 4)

Group like terms

- 2 y + 4 y - y + 2 y - (3 y - 1) - 3 + 5 + 2 - 5 = - (y - 4)

Add similar elements:

- 2 y + 4 y - y + 2 y = 3 y

3 y - (3 y - 1) - 3 + 5 + 2 - 5 = - (y - 4)

Expand

3 y - (3 y - 1) - 3 + 5 + 2 - 5 : 0

Expand

- (y - 4) : - y + 4

0 = - y + 4

Move

0

to the right side

= - y + 4

Move

y

to the left side

y = 4

x, 4 y = 2 x - 8

x - 5 = 2 x

\frac{2 z - 1}{3} + 1 = \frac{3 z - 1}{3}

x, 2 x - 3 y - 7 = 0

y, x - 4 y = 1

What is the answer to -2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4) ?
The answer to -2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4) is y=4
Solve for y: -2y-3-(-4)y+5+[-y+2-(3y-1)+2y-5]=-(y-4)
The solution is y=4