What is the answer to S=(72)/(1+9e^{-36(3))} ?

The answer to S=(72)/(1+9e^{-36(3))} is S=(72e^{108})/(e^{108)+9}

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S=(72)/(1+9e^{-36(3))}

S = \frac{72}{1 + 9 e ^{- 36 (3)}}

S = \frac{72 e ^{108}}{e ^{108} + 9}

Decimal Notation

S = 72

Solution steps

S = \frac{72}{1 + 9 e ^{- 36 (3)}}

Simplify

\frac{72}{1 + 9 e ^{- 36 (3)}} : \frac{72 e ^{108}}{e ^{108} + 9}

S = \frac{72 e ^{108}}{e ^{108} + 9}

\frac{8}{3} x + \frac{5}{7} (x + 9) = \frac{2}{5} (2 x - 7)

\frac{1}{4} - \frac{2}{3} x = - \frac{1}{3}

(x - 1) lo g_{10} (2) + lo g_{10} (8) = lo g_{10} (4)

x, 5 x - y - 6 = 0

\frac{x}{- 5} = 3

What is the answer to S=(72)/(1+9e^{-36(3))} ?
The answer to S=(72)/(1+9e^{-36(3))} is S=(72e^{108})/(e^{108)+9}