What are the solutions to the equation 0=-16t^2+96t+880 ?

The solutions to the equation 0=-16t^2+96t+880 are t=-5,t=11

Find the zeros of 0=-16t^2+96t+880

The zeros of 0=-16t^2+96t+880 are t=-5,t=11

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0 = - 16 t^{2} + 96 t + 880

t = - 5, t = 11

Solution steps

0 = - 16 t^{2} + 96 t + 880

Switch sides

- 16 t^{2} + 96 t + 880 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 880}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 880 = 256

t_{1, 2} = \frac{- 96 \pm 256}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 256}{2 ( - 16 )}, t_{2} = \frac{- 96 - 256}{2 ( - 16 )}

t = \frac{- 96 + 256}{2 ( - 16 )} : - 5

t = \frac{- 96 - 256}{2 ( - 16 )} : 11

The solutions to the quadratic equation are:

t = - 5, t = 11

- 5 x^{3} - 4 x^{2} + x

∣ x - 2 ∣ > 6

0 = 32 t - 16 t^{2}

4 c i s (- \frac{2 π}{3})

a^{2} - 12 a + 20

What are the solutions to the equation 0=-16t^2+96t+880 ?
The solutions to the equation 0=-16t^2+96t+880 are t=-5,t=11
Find the zeros of 0=-16t^2+96t+880
The zeros of 0=-16t^2+96t+880 are t=-5,t=11