What are the solutions to the equation 2x-x^2=0 ?

The solutions to the equation 2x-x^2=0 are x=0,x=2

Find the zeros of 2x-x^2=0

The zeros of 2x-x^2=0 are x=0,x=2

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2 x - x^{2} = 0

x = 0, x = 2

Solution steps

2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2}{2 ( - 1 )}

x = \frac{- 2 + 2}{2 ( - 1 )} : 0

x = \frac{- 2 - 2}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

2 v^{2} + 5 v + 2

- 4 x^{2} + 8 = 0

5 x + 1 = 11

2 x^{2} - x - 55

(5 x + 1)^{2} = 6

What are the solutions to the equation 2x-x^2=0 ?
The solutions to the equation 2x-x^2=0 are x=0,x=2
Find the zeros of 2x-x^2=0
The zeros of 2x-x^2=0 are x=0,x=2