What is the answer to 5x+3(x-2)-(x+1)^2=x(2-x) ?

The answer to 5x+3(x-2)-(x+1)^2=x(2-x) is x= 7/4

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5x+3(x-2)-(x+1)^2=x(2-x)

5 x + 3 (x - 2) - (x + 1)^{2} = x (2 - x)

x = \frac{7}{4}

Decimal Notation

x = 1.75

Solution steps

5 x + 3 (x - 2) - (x + 1)^{2} = x (2 - x)

Expand

5 x + 3 (x - 2) - (x + 1)^{2} : - x^{2} + 6 x - 7

Expand

x (2 - x) : 2 x - x^{2}

- x^{2} + 6 x - 7 = 2 x - x^{2}

Move

7

to the right side

- x^{2} + 6 x = 2 x - x^{2} + 7

Subtract

2 x - x^{2}

from both sides

- x^{2} + 6 x - (2 x - x^{2}) = 2 x - x^{2} + 7 - (2 x - x^{2})

Simplify

4 x = 7

Divide both sides by

4

x = \frac{7}{4}

4 p + 25 = 6 (p - 3) - 3 (4 - 3 p)

3 - 2 (2 x + 1) = x + 17

\frac{6}{9} = \frac{u}{12}

2 x - 1 = 6 + x

\frac{1}{3} (6 x - 5) - x = \frac{1}{3} - 2 (x + 1)

What is the answer to 5x+3(x-2)-(x+1)^2=x(2-x) ?
The answer to 5x+3(x-2)-(x+1)^2=x(2-x) is x= 7/4
Solve for x: 5x+3(x-2)-(x+1)^2=x(2-x)
The solution is x= 7/4