What is factor x^2+x+1/4 ?

The solution to factor x^2+x+1/4 is (x+1/2)^2

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factor x^2+x+1/4

factor

x^{2} + x + \frac{1}{4}

(x + \frac{1}{2})^{2}

Solution steps

x^{2} + x + \frac{1}{4}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

\frac{1}{4} = (\frac{1}{2})^{2}

x = 2 x \frac{1}{2}

= x^{2} + 2 x \frac{1}{2} + (\frac{1}{2})^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \frac{1}{2} + (\frac{1}{2})^{2} = (x + \frac{1}{2})^{2}

= (x + \frac{1}{2})^{2}

\frac{5 a}{5 a + 5} \cdot \frac{10 a + 10}{a}

100 x^{2} + 20 x + 1

lo g_{9} (2 x - 1) < 0.5

2 x - 1 = 0

\frac{4}{9} - \frac{1}{9}