What is the answer to f=(0^2+1)^3(0^3-2)^2 ?

The answer to f=(0^2+1)^3(0^3-2)^2 is f=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f=(0^2+1)^3(0^3-2)^2

f = (0^{2} + 1)^{3} (0^{3} - 2)^{2}

f = 4

Solution steps

f = (0^{2} + 1)^{3} (0^{3} - 2)^{2}

Simplify

(0^{2} + 1)^{3} (0^{3} - 2)^{2} : 4

f = 4

- \frac{2}{3} p = 20

\frac{5 ( x + 2 )}{3} - \frac{x - 1}{3} = 1

x, 6 x - 24 = - 18 y

2 x + 10 = x + 15

(x - 3)^{2} - x (x - 5) = (x + 4) (x - 3) - (x + 2) (x + 1) + 26

What is the answer to f=(0^2+1)^3(0^3-2)^2 ?
The answer to f=(0^2+1)^3(0^3-2)^2 is f=4
Solve for f: f=(0^2+1)^3(0^3-2)^2
The solution is f=4