What are the solutions to the equation 35n^2+81n+40=0 ?

The solutions to the equation 35n^2+81n+40=0 are n=-5/7 ,n=-8/5

Find the zeros of 35n^2+81n+40=0

The zeros of 35n^2+81n+40=0 are n=-5/7 ,n=-8/5

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35 n^{2} + 81 n + 40 = 0

n = - \frac{5}{7}, n = - \frac{8}{5}

Solution steps

35 n^{2} + 81 n + 40 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 81 \pm 8 1 ^{2} - 4 \cdot 35 \cdot 40}{2 \cdot 35}

8 1^{2} - 4 \cdot 35 \cdot 40 = 31

n_{1, 2} = \frac{- 81 \pm 31}{2 \cdot 35}

Separate the solutions

n_{1} = \frac{- 81 + 31}{2 \cdot 35}, n_{2} = \frac{- 81 - 31}{2 \cdot 35}

n = \frac{- 81 + 31}{2 \cdot 35} : - \frac{5}{7}

n = \frac{- 81 - 31}{2 \cdot 35} : - \frac{8}{5}

The solutions to the quadratic equation are:

n = - \frac{5}{7}, n = - \frac{8}{5}

\frac{m ^{\frac{- 5}{2}}}{m ^{- 2}}

x^{2} - 6 x y + 9 y^{2}

- 4 x - 1 = - 3 x + 5

10 + x \leq - 10

x^{2} + 15 x + 44 \geq 0

What are the solutions to the equation 35n^2+81n+40=0 ?
The solutions to the equation 35n^2+81n+40=0 are n=-5/7 ,n=-8/5
Find the zeros of 35n^2+81n+40=0
The zeros of 35n^2+81n+40=0 are n=-5/7 ,n=-8/5