What is (2k)/(3k-7)-3/(8k) ?

The solution to (2k)/(3k-7)-3/(8k) is (16k^2-9k+21)/(8k(3k-7))

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simplify (2k)/(3k-7)-3/(8k)

simplify

\frac{2 k}{3 k - 7} - \frac{3}{8 k}

\frac{16 k ^{2} - 9 k + 21}{8 k ( 3 k - 7 )}

Solution steps

\frac{2 k}{3 k - 7} - \frac{3}{8 k}

Least Common Multiplier of

3 k - 7, 8 k : 8 k (3 k - 7)

Adjust Fractions based on the LCM

= \frac{16 k ^{2}}{8 k ( 3 k - 7 )} - \frac{3 ( 3 k - 7 )}{8 k ( 3 k - 7 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{16 k ^{2} - 3 ( 3 k - 7 )}{8 k ( 3 k - 7 )}

Simplify

16 k^{2} - 3 (3 k - 7) : 16 k^{2} - 9 k + 21

= \frac{16 k ^{2} - 9 k + 21}{8 k ( 3 k - 7 )}

x - 1 > x - 3

- 25 + \frac{t}{2} \geq 50

- 3 (2 + 4 k) + 7 (2 k - 1)

e^{0.25}

6 x + 9 = x^{2}

What is (2k)/(3k-7)-3/(8k) ?
The solution to (2k)/(3k-7)-3/(8k) is (16k^2-9k+21)/(8k(3k-7))