What is the answer to -(3y+1)-(-2y+3)=6 ?

The answer to -(3y+1)-(-2y+3)=6 is y=-10

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-(3y+1)-(-2y+3)=6

- (3 y + 1) - (- 2 y + 3) = 6

y = - 10

Solution steps

- (3 y + 1) - (- 2 y + 3) = 6

Expand

- (3 y + 1) - (- 2 y + 3) : - y - 4

- y - 4 = 6

Move

4

to the right side

- y = 10

Divide both sides by

- 1

y = - 10

- 0.45 (20) + 0.6 x = 0.3 (20 + x)

\frac{( x - 1 )}{3} + \frac{( 2 x + 1 )}{5} = \frac{( 3 x - 1 )}{4}

x, y - 5 = 3 (x + 2)

k - 8 = - 8

y, 3 y + \frac{x}{2} - 4 = 8

What is the answer to -(3y+1)-(-2y+3)=6 ?
The answer to -(3y+1)-(-2y+3)=6 is y=-10
Solve for y: -(3y+1)-(-2y+3)=6
The solution is y=-10