What is (4x^3-3x^2)/(2x) ?

The solution to (4x^3-3x^2)/(2x) is (x(4x-3))/2

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simplify (4x^3-3x^2)/(2x)

simplify

\frac{4 x ^{3} - 3 x ^{2}}{2 x}

\frac{x ( 4 x - 3 )}{2}

Solution steps

\frac{4 x ^{3} - 3 x ^{2}}{2 x}

Factor

4 x^{3} - 3 x^{2} : x^{2} (4 x - 3)

= \frac{x ^{2} ( 4 x - 3 )}{2 x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{xx ( 4 x - 3 )}{2 x}

Cancel the common factor:

x

= \frac{x ( 4 x - 3 )}{2}

\frac{( \frac{3}{4} + \frac{7}{8} )}{( \frac{2}{5} - \frac{8}{9} )}

\frac{sec ( θ )}{tan ( θ )}

(1 - sin (x)) (1 + sin (x))

\frac{sin ( 2 x )}{1 + cos ( 2 x )}

(2 x - \frac{1}{8 x})^{2}