What is 4x-7(x+2)<18x-3(7x+4) ?

The solution to 4x-7(x+2)<18x-3(7x+4) is True for all x

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4x-7(x+2)<18x-3(7x+4)

4 x - 7 (x + 2) < 18 x - 3 (7 x + 4)

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

4 x - 7 (x + 2) < 18 x - 3 (7 x + 4)

Expand

- 7 (x + 2) : - 7 x - 14

4 x - 7 x - 14 < 18 x - 3 (7 x + 4)

Add similar elements:

4 x - 7 x = - 3 x

- 3 x - 14 < 18 x - 3 (7 x + 4)

Expand

- 3 (7 x + 4) : - 21 x - 12

- 3 x - 14 < 18 x - 21 x - 12

Add similar elements:

18 x - 21 x = - 3 x

- 3 x - 14 < - 3 x - 12

Move

14

to the right side

- 3 x < - 3 x + 2

Move

3 x

to the left side

0 < 2

Therefore, the solution is

True for all x

10 x - \frac{2 ( x - 4 )}{3} = 4 x

x^{2} + 3 x = 3

(- 2 x - 3) - (- x) \leq 5

5 t^{2} - 26 t = 24

3 n^{2} + 22 n + 7

What is 4x-7(x+2)<18x-3(7x+4) ?
The solution to 4x-7(x+2)<18x-3(7x+4) is True for all x