What are the solutions to the equation x^2+3x=3 ?

The solutions to the equation x^2+3x=3 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2

Find the zeros of x^2+3x=3

The zeros of x^2+3x=3 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2

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x^{2} + 3 x = 3

x = \frac{- 3 + 21}{2}, x = \frac{- 3 - 21}{2}

Decimal Notation

x = 0.79128 \dots, x = - 3.79128 \dots

Solution steps

x^{2} + 3 x = 3

Move

3

to the left side

x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 3) = 21

x_{1, 2} = \frac{- 3 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 21}{2 \cdot 1}, x_{2} = \frac{- 3 - 21}{2 \cdot 1}

x = \frac{- 3 + 21}{2 \cdot 1} : \frac{- 3 + 21}{2}

x = \frac{- 3 - 21}{2 \cdot 1} : \frac{- 3 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{2}, x = \frac{- 3 - 21}{2}

(- 2 x - 3) - (- x) \leq 5

5 t^{2} - 26 t = 24

3 n^{2} + 22 n + 7

\frac{5 x - 2}{6} + \frac{2 - 4 x}{5} = 1

(- 12)^{2} + x^{2} = 1 3^{2}

What are the solutions to the equation x^2+3x=3 ?
The solutions to the equation x^2+3x=3 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2
Find the zeros of x^2+3x=3
The zeros of x^2+3x=3 are x=(-3+sqrt(21))/2 ,x=(-3-sqrt(21))/2