What is 1+sqrt(100)+12*2^2-5*(36-29) ?

The solution to 1+sqrt(100)+12*2^2-5*(36-29) is 24

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simplify 1+sqrt(100)+122^2-5(36-29)

simplify

1 + 100 + 12 \cdot 2^{2} - 5 \cdot (36 - 29)

24

Solution steps

1 + 100 + 12 \cdot 2^{2} - 5 (36 - 29)

100 = 10

12 \cdot 2^{2} = 48

5 (36 - 29) = 35

= 1 + 10 + 48 - 35

Add the numbers:

1 + 10 + 48 - 35 = 24

= 24

2 - 2

\frac{\frac{4}{3} - \frac{2}{6} \cdot \frac{7}{2}}{\frac{2}{3} + \frac{5}{6}}

\frac{2}{7 + 2}

(2 \frac{1}{5} a^{5 m - \frac{3}{4}})^{4} \cdot (\frac{5}{11} a^{\frac{5}{4}})^{4}

x^{2} - 2 x y + y^{2} - 1

What is 1+sqrt(100)+12*2^2-5*(36-29) ?
The solution to 1+sqrt(100)+12*2^2-5*(36-29) is 24