What are the solutions to the equation x^2-16=0 ?

The solutions to the equation x^2-16=0 are x=4,x=-4

Find the zeros of x^2-16=0

The zeros of x^2-16=0 are x=4,x=-4

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x^{2} - 16 = 0

x = 4, x = - 4

Solution steps

x^{2} - 16 = 0

Move

16

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

4 x^{4} + 20 x^{3} + 12 x^{2}

\frac{28}{7}

6 x + 4 (4 - x) = 48

\frac{3 ( x - 5 )}{8} = 4

\frac{\frac{t ^{n} z - t ^{2 n + 1} z ^{2}}{t + t ^{n + 2}} - n t ^{n - 1} z}{t ^{n}}

What are the solutions to the equation x^2-16=0 ?
The solutions to the equation x^2-16=0 are x=4,x=-4
Find the zeros of x^2-16=0
The zeros of x^2-16=0 are x=4,x=-4