What is log_{4}(log_{11}(121))+log_{16}(sqrt(2)) ?

The solution to log_{4}(log_{11}(121))+log_{16}(sqrt(2)) is 5/8

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simplify log_{4}(log_{11}(121))+log_{16}(sqrt(2))

simplify

lo g_{4} (lo g_{11} (121)) + lo g_{16} (2)

\frac{5}{8}

Decimal Notation

0.625

Solution steps

lo g_{4} (lo g_{11} (121)) + lo g_{16} (2)

lo g_{4} (lo g_{11} (121)) = \frac{1}{2}

lo g_{16} (2) = \frac{1}{8}

= \frac{1}{2} + \frac{1}{8}

\frac{1}{2} + \frac{1}{8} = \frac{5}{8}

= \frac{5}{8}

x \frac{1}{3} - y \frac{1}{4}

\frac{csc ( θ )}{sin ( θ )}

3 y^{2}

1 \cdot 6

(7 a^{2} + 5 a + 3) + (- 3 a^{2} + 2 a - 4)

What is log_{4}(log_{11}(121))+log_{16}(sqrt(2)) ?
The solution to log_{4}(log_{11}(121))+log_{16}(sqrt(2)) is 5/8