What are the solutions to the equation 4x^2+36x=-85 ?

The solutions to the equation 4x^2+36x=-85 are x=-9/2+i,x=-9/2-i

Find the zeros of 4x^2+36x=-85

The zeros of 4x^2+36x=-85 are x=-9/2+i,x=-9/2-i

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4 x^{2} + 36 x = - 85

x = - \frac{9}{2} + i, x = - \frac{9}{2} - i

Solution steps

4 x^{2} + 36 x = - 85

Move

85

to the left side

4 x^{2} + 36 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 85}{2 \cdot 4}

Simplify

3 6^{2} - 4 \cdot 4 \cdot 85 : 8 i

x_{1, 2} = \frac{- 36 \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 8 i}{2 \cdot 4}, x_{2} = \frac{- 36 - 8 i}{2 \cdot 4}

x = \frac{- 36 + 8 i}{2 \cdot 4} : - \frac{9}{2} + i

x = \frac{- 36 - 8 i}{2 \cdot 4} : - \frac{9}{2} - i

The solutions to the quadratic equation are:

x = - \frac{9}{2} + i, x = - \frac{9}{2} - i

lo g_{2} (2^{8})

5 x^{2} + 9 x - 38 = 0

\frac{1}{6} + \frac{3}{4}

4 + g \geq 3 or 6 g \geq - 30

5 ∣ x - 1 ∣ + 5 < 40

What are the solutions to the equation 4x^2+36x=-85 ?
The solutions to the equation 4x^2+36x=-85 are x=-9/2+i,x=-9/2-i
Find the zeros of 4x^2+36x=-85
The zeros of 4x^2+36x=-85 are x=-9/2+i,x=-9/2-i