What are the solutions to the equation 5x^2+9x-38=0 ?

The solutions to the equation 5x^2+9x-38=0 are x=2,x=-19/5

Find the zeros of 5x^2+9x-38=0

The zeros of 5x^2+9x-38=0 are x=2,x=-19/5

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5 x^{2} + 9 x - 38 = 0

x = 2, x = - \frac{19}{5}

Decimal Notation

x = 2, x = - 3.8

Solution steps

5 x^{2} + 9 x - 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 38 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 38) = 29

x_{1, 2} = \frac{- 9 \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 29}{2 \cdot 5}, x_{2} = \frac{- 9 - 29}{2 \cdot 5}

x = \frac{- 9 + 29}{2 \cdot 5} : 2

x = \frac{- 9 - 29}{2 \cdot 5} : - \frac{19}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{19}{5}

\frac{1}{6} + \frac{3}{4}

4 + g \geq 3 or 6 g \geq - 30

5 ∣ x - 1 ∣ + 5 < 40

2 x^{2} + 6 x + 3 = 0

t^{2} + 6 t = 16

What are the solutions to the equation 5x^2+9x-38=0 ?
The solutions to the equation 5x^2+9x-38=0 are x=2,x=-19/5
Find the zeros of 5x^2+9x-38=0
The zeros of 5x^2+9x-38=0 are x=2,x=-19/5