What are the solutions to the equation t^2+6t=16 ?

The solutions to the equation t^2+6t=16 are t=2,t=-8

Find the zeros of t^2+6t=16

The zeros of t^2+6t=16 are t=2,t=-8

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t^{2} + 6 t = 16

t = 2, t = - 8

Solution steps

t^{2} + 6 t = 16

Move

16

to the left side

t^{2} + 6 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

t_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 6 + 10}{2 \cdot 1}, t_{2} = \frac{- 6 - 10}{2 \cdot 1}

t = \frac{- 6 + 10}{2 \cdot 1} : 2

t = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

t = 2, t = - 8

2 x^{2} - 9 x = 5

7 x^{2} - 34 x - 5 = 0

x^{2} - 12 x + 12 = 0

42 - 35 + 42 + 85

7 - (3.1 - 0.1 y) = 3 - 0.2 y

What are the solutions to the equation t^2+6t=16 ?
The solutions to the equation t^2+6t=16 are t=2,t=-8
Find the zeros of t^2+6t=16
The zeros of t^2+6t=16 are t=2,t=-8