What are the solutions to the equation 2x^2-9x=5 ?

The solutions to the equation 2x^2-9x=5 are x=5,x=-1/2

Find the zeros of 2x^2-9x=5

The zeros of 2x^2-9x=5 are x=5,x=-1/2

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2 x^{2} - 9 x = 5

x = 5, x = - \frac{1}{2}

Decimal Notation

x = 5, x = - 0.5

Solution steps

2 x^{2} - 9 x = 5

Move

5

to the left side

2 x^{2} - 9 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 5) = 11

x_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 2}

x = \frac{- ( - 9 ) + 11}{2 \cdot 2} : 5

x = \frac{- ( - 9 ) - 11}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{1}{2}

7 x^{2} - 34 x - 5 = 0

x^{2} - 12 x + 12 = 0

42 - 35 + 42 + 85

7 - (3.1 - 0.1 y) = 3 - 0.2 y

9 x^{2} - 16 y^{2}

What are the solutions to the equation 2x^2-9x=5 ?
The solutions to the equation 2x^2-9x=5 are x=5,x=-1/2
Find the zeros of 2x^2-9x=5
The zeros of 2x^2-9x=5 are x=5,x=-1/2