What is 1/(\frac{1){x+2}+1/(x+3)} ?

The solution to 1/(\frac{1){x+2}+1/(x+3)} is ((x+2)(x+3))/(2x+5)

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simplify 1/(\frac{1){x+2}+1/(x+3)}

simplify

\frac{1}{\frac{1}{x + 2} + \frac{1}{x + 3}}

\frac{( x + 2 ) ( x + 3 )}{2 x + 5}

Solution steps

\frac{1}{\frac{1}{x + 2} + \frac{1}{x + 3}}

Join

\frac{1}{x + 2} + \frac{1}{x + 3} : \frac{2 x + 5}{( x + 2 ) ( x + 3 )}

= \frac{1}{\frac{2 x + 5}{( x + 2 ) ( x + 3 )}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{( x + 2 ) ( x + 3 )}{2 x + 5}

z^{- 1}

11 \cdot 4

8 s^{2} + 9 s + 1

(5 + 12 i) + (10 i - 8) + (6 i + 3) + (7 + 2 i)

2 \cdot (- x)

What is 1/(\frac{1){x+2}+1/(x+3)} ?
The solution to 1/(\frac{1){x+2}+1/(x+3)} is ((x+2)(x+3))/(2x+5)