What is (5+12i)+(10i-8)+(6i+3)+(7+2i) ?

The solution to (5+12i)+(10i-8)+(6i+3)+(7+2i) is 7+30i

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simplify (5+12i)+(10i-8)+(6i+3)+(7+2i)

simplify

(5 + 12 i) + (10 i - 8) + (6 i + 3) + (7 + 2 i)

7 + 30 i

Solution steps

(5 + 12 i) + (10 i - 8) + (6 i + 3) + (7 + 2 i)

Simplify

(5 + 12 i) + (10 i - 8) + (6 i + 3) + (7 + 2 i) : 5 + 12 i + 10 i - 8 + 6 i + 3 + 7 + 2 i

= 5 + 12 i + 10 i - 8 + 6 i + 3 + 7 + 2 i

Group like terms

= 12 i + 10 i + 6 i + 2 i + 5 - 8 + 3 + 7

Add similar elements:

12 i + 10 i + 6 i + 2 i = 30 i

= 30 i + 5 - 8 + 3 + 7

Add the numbers:

5 - 8 + 3 + 7 = 7

= 30 i + 7

Rewrite in standard complex form:

7 + 30 i

= 7 + 30 i

2 \cdot (- x)

(5 + 12 i) + [(10 - 8 i) + [(6 + 3 i) - (7 + 2 i)]]

2 sin (3 θ) cos (3 θ)

a b^{3}

(x + 5) (x - 5) (x^{2} + 25) (x^{4} + 625) + 62 5^{2}

What is (5+12i)+(10i-8)+(6i+3)+(7+2i) ?
The solution to (5+12i)+(10i-8)+(6i+3)+(7+2i) is 7+30i