What is expand (x-1)(x-2)(x+3)(x+4) ?

The solution to expand (x-1)(x-2)(x+3)(x+4) is x^4+4x^3-7x^2-22x+24

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expand (x-1)(x-2)(x+3)(x+4)

expand

(x - 1) (x - 2) (x + 3) (x + 4)

x^{4} + 4 x^{3} - 7 x^{2} - 22 x + 24

Solution steps

(x - 1) (x - 2) (x + 3) (x + 4)

Expand

(x - 1) (x - 2) (x + 3) (x + 4) : (x^{2} - 3 x + 2) (x + 3) (x + 4)

= (x^{2} - 3 x + 2) (x + 3) (x + 4)

Apply FOIL method

(x + 3) (x + 4) : x^{2} + 7 x + 12

= (x^{2} - 3 x + 2) (x^{2} + 7 x + 12)

Distribute parentheses

= x^{2} x^{2} + x^{2} \cdot 7 x + x^{2} \cdot 12 - 3 x x^{2} - 3 x \cdot 7 x - 3 x \cdot 12 + 2 x^{2} + 2 \cdot 7 x + 2 \cdot 12

Simplify

x^{2} x^{2} + x^{2} \cdot 7 x + x^{2} \cdot 12 - 3 x x^{2} - 3 x \cdot 7 x - 3 x \cdot 12 + 2 x^{2} + 2 \cdot 7 x + 2 \cdot 12 : x^{4} + 4 x^{3} - 7 x^{2} - 22 x + 24

= x^{4} + 4 x^{3} - 7 x^{2} - 22 x + 24

\frac{\frac{n + 3}{2 n - 6}}{\frac{n + 3}{3 n - 9}}

(x + 1)^{2} - 9

a - (b + a) + (- a + b) - (- a + 2 b)

(6 i - 2) + (3 - 4 i)

4 x^{3}

What is expand (x-1)(x-2)(x+3)(x+4) ?
The solution to expand (x-1)(x-2)(x+3)(x+4) is x^4+4x^3-7x^2-22x+24