What is (a^3+4a^2+3a)/(a^2+a-6) ?

The solution to (a^3+4a^2+3a)/(a^2+a-6) is (a(a+1))/(a-2)

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simplify (a^3+4a^2+3a)/(a^2+a-6)

simplify

\frac{a ^{3} + 4 a ^{2} + 3 a}{a ^{2} + a - 6}

\frac{a ( a + 1 )}{a - 2}

Solution steps

\frac{a ^{3} + 4 a ^{2} + 3 a}{a ^{2} + a - 6}

Factor

a^{3} + 4 a^{2} + 3 a : a (a + 1) (a + 3)

= \frac{a ( a + 1 ) ( a + 3 )}{a ^{2} + a - 6}

Factor

a^{2} + a - 6 : (a - 2) (a + 3)

= \frac{a ( a + 1 ) ( a + 3 )}{( a - 2 ) ( a + 3 )}

Cancel the common factor:

a + 3

= \frac{a ( a + 1 )}{a - 2}

cos^{2} (- sin^{2} (x))

(2 x + 1) (3 x + 1)

\frac{2 ^{a + 3} - 2 ^{a + 1}}{3 \cdot 2 ^{a}}

0.8 \cdot 9.8 \cdot 15

(3 + 4 i) - (6 - 3 i)

What is (a^3+4a^2+3a)/(a^2+a-6) ?
The solution to (a^3+4a^2+3a)/(a^2+a-6) is (a(a+1))/(a-2)