What is (3+4i)-(6-3i) ?

The solution to (3+4i)-(6-3i) is -3+7i

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simplify (3+4i)-(6-3i)

simplify

(3 + 4 i) - (6 - 3 i)

- 3 + 7 i

Solution steps

(3 + 4 i) - (6 - 3 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 6) + (4 - (- 3)) i

Simplify

(3 - 6) + (4 - (- 3)) i : - 3 + 7 i

= - 3 + 7 i

\frac{12 x y ^{2} + 20 x ^{2} yz - 10 y ^{2}}{10 y ^{2}}

(3 + 5 i) (2 - 7 i)

5^{3} \cdot 5^{2}

\frac{csc ( θ )}{cot ( θ )}