What is (((x^2y^{-3})^{1/4}))/(x^{-1)y^2} ?

The solution to (((x^2y^{-3})^{1/4}))/(x^{-1)y^2} is (x^{3/2})/(y^{11/4)}

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simplify (((x^2y^{-3})^{1/4}))/(x^{-1)y^2}

simplify

\frac{( ( x ^{2} y ^{- 3} ) ^{\frac{1}{4}} )}{x ^{- 1} y ^{2}}

\frac{x ^{\frac{3}{2}}}{y ^{\frac{11}{4}}}

Solution steps

\frac{( x ^{2} y ^{- 3} ) ^{\frac{1}{4}}}{x ^{- 1} y ^{2}}

Simplify

(x^{2} y^{- 3})^{\frac{1}{4}} : x^{\frac{1}{2}} \frac{1}{y ^{\frac{3}{4}}}

= \frac{x ^{\frac{1}{2}} \frac{1}{y ^{\frac{3}{4}}}}{x ^{- 1} y ^{2}}

Simplify

\frac{x ^{\frac{1}{2}}}{x ^{- 1}} : x^{\frac{3}{2}}

= \frac{x ^{\frac{3}{2}} \frac{1}{y ^{\frac{3}{4}}}}{y ^{2}}

Simplify

\frac{x ^{\frac{3}{2}} \frac{1}{y ^{\frac{3}{4}}}}{y ^{2}} : \frac{x ^{\frac{3}{2}}}{y ^{\frac{11}{4}}}

= \frac{x ^{\frac{3}{2}}}{y ^{\frac{11}{4}}}

(1 - sin (θ)) (1 + sin (θ))

2 cos^{2} (2 x) - 2 sin^{2} (2 x)

(x + 1)^{2} + (x + 4)^{2} - 2 x^{2} - 10 x

\frac{sec ( θ )}{cos ( θ )}

(a + b)^{20}

What is (((x^2y^{-3})^{1/4}))/(x^{-1)y^2} ?
The solution to (((x^2y^{-3})^{1/4}))/(x^{-1)y^2} is (x^{3/2})/(y^{11/4)}