What are the solutions to the equation x^2-12x+36=4 ?

The solutions to the equation x^2-12x+36=4 are x=8,x=4

Find the zeros of x^2-12x+36=4

The zeros of x^2-12x+36=4 are x=8,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 12 x + 36 = 4

x = 8, x = 4

Solution steps

x^{2} - 12 x + 36 = 4

Move

4

to the left side

x^{2} - 12 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 32 = 4

x_{1, 2} = \frac{- ( - 12 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4}{2 \cdot 1} : 8

x = \frac{- ( - 12 ) - 4}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 8, x = 4

9 x y^{2} \cdot 9 x^{5} y^{2}

\frac{x}{4} + \frac{2}{5} = 4

x^{2} - x = 12

2 x^{3} + 14 x^{2} + 20 x

1 - \frac{1}{4}

What are the solutions to the equation x^2-12x+36=4 ?
The solutions to the equation x^2-12x+36=4 are x=8,x=4
Find the zeros of x^2-12x+36=4
The zeros of x^2-12x+36=4 are x=8,x=4