What is the answer to |x^2-x|=12 ?

The answer to |x^2-x|=12 is x=-3\lor x=4

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|x^2-x|=12

x^{2} - x = 12

x = - 3 or x = 4

Solution steps

x^{2} - x = 12

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - x = - 12 or x^{2} - x = 12

x^{2} - x = - 12 or x^{2} - x = 12

No Solution or (x = - 3 or x = 4)

x = - 3 or x = 4

2 x^{3} + 14 x^{2} + 20 x

1 - \frac{1}{4}

\frac{960 ( 1 )}{( ( 1 ) ^{2} + 4 ) ^{2}}

x^{2} + 12 x = 20

(\frac{8}{7})^{- 2}