What is (3^{-1}-3^{-2})/((3^{-1))(3^{-2})} ?

The solution to (3^{-1}-3^{-2})/((3^{-1))(3^{-2})} is 6

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simplify (3^{-1}-3^{-2})/((3^{-1))(3^{-2})}

simplify

\frac{3 ^{- 1} - 3 ^{- 2}}{( 3 ^{- 1} ) ( 3 ^{- 2} )}

6

Solution steps

\frac{3 ^{- 1} - 3 ^{- 2}}{( 3 ^{- 1} ) ( 3 ^{- 2} )}

Remove parentheses:

(a) = a

= \frac{3 ^{- 1} - 3 ^{- 2}}{3 ^{- 1} \cdot 3 ^{- 2}}

3^{- 1} \cdot 3^{- 2} = 3^{- 3}

= \frac{3 ^{- 1} - 3 ^{- 2}}{3 ^{- 3}}

Simplify

3^{- 1} - 3^{- 2} : \frac{1}{3} - \frac{1}{3 ^{2}}

= \frac{\frac{1}{3} - \frac{1}{3 ^{2}}}{3 ^{- 3}}

Join

\frac{1}{3} - \frac{1}{3 ^{2}} : \frac{2}{9}

= \frac{\frac{2}{9}}{3 ^{- 3}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2}{9 \cdot 3 ^{- 3}}

3^{- 3} = \frac{1}{27}

= \frac{2}{9 \cdot \frac{1}{27}}

Multiply

9 \cdot \frac{1}{27} : \frac{1}{3}

= \frac{2}{\frac{1}{3}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{2 \cdot 3}{1}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6}{1}

Apply rule

\frac{a}{1} = a

= 6

(3 - 2 i) (- 2 + 4 i)

x (2 x - 3)

p lo g_{b} (A) - q lo g_{b} (b) + r lo g_{b} (C)

\frac{\frac{( a ^{2} b )}{( 2 a )}}{( a b ^{2} )}

What is (3^{-1}-3^{-2})/((3^{-1))(3^{-2})} ?
The solution to (3^{-1}-3^{-2})/((3^{-1))(3^{-2})} is 6