What are the solutions to the equation 3x+{-5x(x+3)}=8x+(-5-9) ?

The solutions to the equation 3x+{-5x(x+3)}=8x+(-5-9) are x=-(10+sqrt(170))/5 ,x=(sqrt(170)-10)/5

Find the zeros of 3x+{-5x(x+3)}=8x+(-5-9)

The zeros of 3x+{-5x(x+3)}=8x+(-5-9) are x=-(10+sqrt(170))/5 ,x=(sqrt(170)-10)/5

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3 x + {- 5 x (x + 3)} = 8 x + (- 5 - 9)

x = - \frac{10 + 170}{5}, x = \frac{170 - 10}{5}

Solution steps

3 x + {- 5 x (x + 3)} = 8 x + (- 5 - 9)

Expand

3 x + (- 5 x (x + 3)) : - 5 x^{2} - 12 x

- 5 x^{2} - 12 x = 8 x - 14

Move

14

to the left side

- 5 x^{2} - 12 x + 14 = 8 x

Move

8 x

to the left side

- 5 x^{2} - 20 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 5 ) \cdot 14}{2 ( - 5 )}

(- 20)^{2} - 4 (- 5) \cdot 14 = 2170

x_{1, 2} = \frac{- ( - 20 ) \pm 2 170}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 170}{2 ( - 5 )}, x_{2} = \frac{- ( - 20 ) - 2 170}{2 ( - 5 )}

x = \frac{- ( - 20 ) + 2 170}{2 ( - 5 )} : - \frac{10 + 170}{5}

x = \frac{- ( - 20 ) - 2 170}{2 ( - 5 )} : \frac{170 - 10}{5}

The solutions to the quadratic equation are:

x = - \frac{10 + 170}{5}, x = \frac{170 - 10}{5}

6 x^{2} - 18 x - 60 = 108

(- \frac{3}{2})^{5}

\frac{5}{3 ^{3}}

(2 x - 7) (x + 5) \geq 0

((3 x - 1) - 3)^{2} \leq (3 x + 1)^{2}

What are the solutions to the equation 3x+{-5x(x+3)}=8x+(-5-9) ?
The solutions to the equation 3x+{-5x(x+3)}=8x+(-5-9) are x=-(10+sqrt(170))/5 ,x=(sqrt(170)-10)/5
Find the zeros of 3x+{-5x(x+3)}=8x+(-5-9)
The zeros of 3x+{-5x(x+3)}=8x+(-5-9) are x=-(10+sqrt(170))/5 ,x=(sqrt(170)-10)/5