What are the solutions to the equation pir^2=2 ?

The solutions to the equation pir^2=2 are r=sqrt(2/pi),r=-sqrt(2/pi)

Find the zeros of pir^2=2

The zeros of pir^2=2 are r=sqrt(2/pi),r=-sqrt(2/pi)

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π r^{2} = 2

r = \frac{2}{π}, r = - \frac{2}{π}

Decimal

r = 0.79788 \dots, r = - 0.79788 \dots

Solution steps

π r^{2} = 2

Divide both sides by

π

r^{2} = \frac{2}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{2}{π}, r = - \frac{2}{π}

\frac{k}{2} - 1 \geq 3

\frac{1}{3 i}

15 - 20 x \geq - 9 + 10 x

lo g_{8} (512) = x

5 v + 10 \leq - 4 v - 17 < 9 - 2 v

What are the solutions to the equation pir^2=2 ?
The solutions to the equation pir^2=2 are r=sqrt(2/pi),r=-sqrt(2/pi)
Find the zeros of pir^2=2
The zeros of pir^2=2 are r=sqrt(2/pi),r=-sqrt(2/pi)