What is 5v+10<=-4v-17<9-2v ?

The solution to 5v+10<=-4v-17<9-2v is -13<v<=-3

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5v+10<=-4v-17<9-2v

5 v + 10 \leq - 4 v - 17 < 9 - 2 v

- 13 < v \leq - 3

Interval Notation

(- 13, - 3]

Solution steps

5 v + 10 \leq - 4 v - 17 < 9 - 2 v

a \leq u < b

then

a \leq u and u < b

5 v + 10 \leq - 4 v - 17 and - 4 v - 17 < 9 - 2 v

5 v + 10 \leq - 4 v - 17 : v \leq - 3

- 4 v - 17 < 9 - 2 v : v > - 13

Combine the intervals

v \leq - 3 and v > - 13

Merge Overlapping Intervals

- 13 < v \leq - 3

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\frac{c}{3} = \frac{30}{5}

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