What is (x+1-i)(x+1+i) ?

The solution to (x+1-i)(x+1+i) is x^2+2x+2

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simplify (x+1-i)(x+1+i)

simplify

(x + 1 - i) (x + 1 + i)

x^{2} + 2 x + 2

Solution steps

(x + 1 - i) (x + 1 + i)

Rewrite

x + 1 - i

in standard complex form:

(x + 1) - i

= ((x + 1) - i) (x + 1 + i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (x + 1)^{2} + (- 1)^{2}

Simplify

(x + 1)^{2} + (- 1)^{2} : x^{2} + 2 x + 2

= x^{2} + 2 x + 2

(d - \frac{1}{n})^{2}

\frac{( - 10 x ^{3} + 30 x - 20 )}{( - 5 x + 5 )}

6.75

20 \cdot 1 0^{- 3}

(x a + a x)^{2}