What are the solutions to the equation 2x^2-11x-1=0 ?

The solutions to the equation 2x^2-11x-1=0 are x=(11+sqrt(129))/4 ,x=(11-sqrt(129))/4

Find the zeros of 2x^2-11x-1=0

The zeros of 2x^2-11x-1=0 are x=(11+sqrt(129))/4 ,x=(11-sqrt(129))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 11 x - 1 = 0

x = \frac{11 + 129}{4}, x = \frac{11 - 129}{4}

Decimal Notation

x = 5.58945 \dots, x = - 0.08945 \dots

Solution steps

2 x^{2} - 11 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 1) = 129

x_{1, 2} = \frac{- ( - 11 ) \pm 129}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 129}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 129}{2 \cdot 2}

x = \frac{- ( - 11 ) + 129}{2 \cdot 2} : \frac{11 + 129}{4}

x = \frac{- ( - 11 ) - 129}{2 \cdot 2} : \frac{11 - 129}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 129}{4}, x = \frac{11 - 129}{4}

- 9 x + 2 > 18

\frac{2}{8}

8 n^{2} < 64 n \cdot lo g_{2} (n)

x^{6} - x^{4} + 2 x^{3} - 6 x^{2} + 4 x \geq 0

9 p^{2} - 17 p - 2

What are the solutions to the equation 2x^2-11x-1=0 ?
The solutions to the equation 2x^2-11x-1=0 are x=(11+sqrt(129))/4 ,x=(11-sqrt(129))/4
Find the zeros of 2x^2-11x-1=0
The zeros of 2x^2-11x-1=0 are x=(11+sqrt(129))/4 ,x=(11-sqrt(129))/4