What is (2^2*3^3*5^7)/(3^2*5^6*2^2) ?

The solution to (2^2*3^3*5^7)/(3^2*5^6*2^2) is 15

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simplify (2^23^35^7)/(3^25^62^2)

simplify

\frac{2 ^{2} \cdot 3 ^{3} \cdot 5 ^{7}}{3 ^{2} \cdot 5 ^{6} \cdot 2 ^{2}}

15

Solution steps

\frac{2 ^{2} \cdot 3 ^{3} \cdot 5 ^{7}}{3 ^{2} \cdot 5 ^{6} \cdot 2 ^{2}}

Cancel the common factor:

2^{2}

= \frac{3 ^{3} \cdot 5 ^{7}}{3 ^{2} \cdot 5 ^{6}}

\frac{3 ^{3}}{3 ^{2}} = 3

= \frac{3 \cdot 5 ^{7}}{5 ^{6}}

\frac{5 ^{7}}{5 ^{6}} = 5

= 3 \cdot 5

Multiply the numbers:

3 \cdot 5 = 15

= 15

(2 x - 5) (4 x^{2} + 10 x + 25)

\frac{x}{cos ( x )}

(a^{5} b^{2})^{- 3} \cdot (a^{- 2})^{- 3}

\frac{x + 1}{x ^{2} + 6 x + 9} - \frac{1}{x ^{2} - 9}

lo g_{128} (\frac{1}{64})

What is (2^2*3^3*5^7)/(3^2*5^6*2^2) ?
The solution to (2^2*3^3*5^7)/(3^2*5^6*2^2) is 15