What is (i^{5235}(2-i)^4)/((7i-(4+3i)-2)^3) ?

The solution to (i^{5235}(2-i)^4)/((7i-(4+3i)-2)^3) is -(i(2-i)^4)/((-6+4i)^3)

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simplify (i^{5235}(2-i)^4)/((7i-(4+3i)-2)^3)

simplify

\frac{i ^{5235} ( 2 - i ) ^{4}}{( 7 i - ( 4 + 3 i ) - 2 ) ^{3}}

- \frac{i ( 2 - i ) ^{4}}{( - 6 + 4 i ) ^{3}}

Solution steps

\frac{i ^{5235} ( 2 - i ) ^{4}}{( 7 i - ( 4 + 3 i ) - 2 ) ^{3}}

Simplify

i^{5235} : - i

= \frac{- i ( 2 - i ) ^{4}}{( 7 i - ( 4 + 3 i ) - 2 ) ^{3}}

Simplify

7 i - (4 + 3 i) - 2 : 4 i - 6

= \frac{- i ( 2 - i ) ^{4}}{( 4 i - 6 ) ^{3}}

Rewrite in standard complex form:

- \frac{i ( 2 - i ) ^{4}}{( - 6 + 4 i ) ^{3}}

= - \frac{i ( 2 - i ) ^{4}}{( - 6 + 4 i ) ^{3}}

\frac{9 m}{5 m ^{2}} \cdot \frac{7}{2}

\frac{2 5 - 3}{5 + 1}

\frac{5 3 + 2}{3 - 1}

\frac{x ^{2} + 5 x - 36}{x ^{2} - 49} \cdot (x^{2} - 11 x + 28)

tan (θ) cos (θ) csc (θ)

What is (i^{5235}(2-i)^4)/((7i-(4+3i)-2)^3) ?
The solution to (i^{5235}(2-i)^4)/((7i-(4+3i)-2)^3) is -(i(2-i)^4)/((-6+4i)^3)