What is 9((sqrt(35))/6)^2+3(1/6) ?

The solution to 9((sqrt(35))/6)^2+3(1/6) is 37/4

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simplify 9((sqrt(35))/6)^2+3(1/6)

simplify

9 (\frac{35}{6})^{2} + 3 (\frac{1}{6})

\frac{37}{4}

Decimal Notation

9.25

Solution steps

9 (\frac{35}{6})^{2} + 3 (\frac{1}{6})

Apply rule:

(a) = a

(\frac{1}{6}) = \frac{1}{6}

= 9 (\frac{35}{6})^{2} + 3 \cdot \frac{1}{6}

(\frac{35}{6})^{2} = \frac{35}{36}

3 \cdot \frac{1}{6} = \frac{1}{2}

= 9 \cdot \frac{35}{36} + \frac{1}{2}

9 \cdot \frac{35}{36} + \frac{1}{2} = \frac{37}{2 \cdot 2}

= \frac{37}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{37}{4}

2 sin^{2} (x) - 1

\frac{( 10 i )}{( 1 - 2 i )}

\frac{1}{2} (9.8)

x^{4} - 6 x^{3} - 11 x^{2} + 96 x - 80

[(9 x^{\frac{1}{2}} y^{- 3}) (2 x^{- 1} y)^{2}]^{\frac{1}{2}}

What is 9((sqrt(35))/6)^2+3(1/6) ?
The solution to 9((sqrt(35))/6)^2+3(1/6) is 37/4