What is (x-7)/(-5x+40)*(x^2-64)/(-4x+28) ?

The solution to (x-7)/(-5x+40)*(x^2-64)/(-4x+28) is (x+8)/(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x-7)/(-5x+40)*(x^2-64)/(-4x+28)

simplify

\frac{x - 7}{- 5 x + 40} \cdot \frac{x ^{2} - 64}{- 4 x + 28}

\frac{x + 8}{20}

Solution steps

\frac{x - 7}{- 5 x + 40} \cdot \frac{x ^{2} - 64}{- 4 x + 28}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x - 7 ) ( x ^{2} - 64 )}{( - 5 x + 40 ) ( - 4 x + 28 )}

Factor

- 4 x + 28 : 4 (- x + 7)

= \frac{( x - 7 ) ( x ^{2} - 64 )}{( - 5 x + 40 ) \cdot 4 ( - x + 7 )}

Simplify

\frac{x - 7}{- x + 7} : - 1

= \frac{- ( x ^{2} - 64 )}{( - 5 x + 40 ) \cdot 4}

Factor

x^{2} - 64 : (x + 8) (x - 8)

= \frac{- ( x + 8 ) ( x - 8 )}{( - 5 x + 40 ) \cdot 4}

Factor

- 5 x + 40 : 5 (- x + 8)

= \frac{- ( x + 8 ) ( x - 8 )}{5 ( - x + 8 ) \cdot 4}

Simplify

\frac{x - 8}{- x + 8} : - 1

= \frac{x + 8}{5 \cdot 4}

Multiply the numbers:

5 \cdot 4 = 20

= \frac{x + 8}{20}

(9 x^{2} + 8 x) - (2 x^{2} + 3 x)

(\frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}})^{- 3}

- 20 + - 45

1 - tan^{2} (θ)

\frac{9 n}{2 n} \cdot \frac{7}{5 n}

What is (x-7)/(-5x+40)*(x^2-64)/(-4x+28) ?
The solution to (x-7)/(-5x+40)*(x^2-64)/(-4x+28) is (x+8)/(20)