What are the solutions to the equation -3r^2+27=0 ?

The solutions to the equation -3r^2+27=0 are r=3,r=-3

Find the zeros of -3r^2+27=0

The zeros of -3r^2+27=0 are r=3,r=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 r^{2} + 27 = 0

r = 3, r = - 3

Solution steps

- 3 r^{2} + 27 = 0

Move

27

to the right side

- 3 r^{2} = - 27

Divide both sides by

- 3

r^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 9, r = - 9

9 = 3

- 9 = - 3

r = 3, r = - 3

- x^{2} - 4 x + 4 = 0

5 (2 y) - y = 72

\frac{2 x - 1}{3} = 5

36 - x^{4} y^{4}

k - 3 k = 6 k + 5 - 8 k

What are the solutions to the equation -3r^2+27=0 ?
The solutions to the equation -3r^2+27=0 are r=3,r=-3
Find the zeros of -3r^2+27=0
The zeros of -3r^2+27=0 are r=3,r=-3