What is (n^4+2n^2-48)/(n^2+8) ?

The solution to (n^4+2n^2-48)/(n^2+8) is n^2-6

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simplify (n^4+2n^2-48)/(n^2+8)

simplify

\frac{n ^{4} + 2 n ^{2} - 48}{n ^{2} + 8}

n^{2} - 6

Solution steps

\frac{n ^{4} + 2 n ^{2} - 48}{n ^{2} + 8}

Factor

n^{4} + 2 n^{2} - 48 : (n^{2} - 6) (n^{2} + 8)

= \frac{( n ^{2} - 6 ) ( n ^{2} + 8 )}{n ^{2} + 8}

Cancel the common factor:

n^{2} + 8

= n^{2} - 6

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