What is (\frac{x^2+9x+20)/(x^2-25)}{(x+4)/(x-4)} ?

The solution to (\frac{x^2+9x+20)/(x^2-25)}{(x+4)/(x-4)} is (x-4)/(x-5)

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simplify (\frac{x^2+9x+20)/(x^2-25)}{(x+4)/(x-4)}

simplify

\frac{\frac{x ^{2} + 9 x + 20}{x ^{2} - 25}}{\frac{x + 4}{x - 4}}

\frac{x - 4}{x - 5}

Solution steps

\frac{\frac{x ^{2} + 9 x + 20}{x ^{2} - 25}}{\frac{x + 4}{x - 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + 9 x + 20 ) ( x - 4 )}{( x ^{2} - 25 ) ( x + 4 )}

Cancel

\frac{( x ^{2} + 9 x + 20 ) ( x - 4 )}{( x ^{2} - 25 ) ( x + 4 )} : \frac{x - 4}{x - 5}

= \frac{x - 4}{x - 5}

6 \frac{64 w ^{6}}{18 w ^{2} x ^{3}}

4 + 1

x \frac{1}{x}

\frac{1}{6} \cdot \frac{5}{6}

825

What is (\frac{x^2+9x+20)/(x^2-25)}{(x+4)/(x-4)} ?
The solution to (\frac{x^2+9x+20)/(x^2-25)}{(x+4)/(x-4)} is (x-4)/(x-5)