What is (4x^2-9)/(2x^2-x-3) ?

The solution to (4x^2-9)/(2x^2-x-3) is (2x+3)/(x+1)

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simplify (4x^2-9)/(2x^2-x-3)

simplify

\frac{4 x ^{2} - 9}{2 x ^{2} - x - 3}

\frac{2 x + 3}{x + 1}

Solution steps

\frac{4 x ^{2} - 9}{2 x ^{2} - x - 3}

Factor

4 x^{2} - 9 : (2 x + 3) (2 x - 3)

= \frac{( 2 x + 3 ) ( 2 x - 3 )}{2 x ^{2} - x - 3}

Factor

2 x^{2} - x - 3 : (x + 1) (2 x - 3)

= \frac{( 2 x + 3 ) ( 2 x - 3 )}{( x + 1 ) ( 2 x - 3 )}

Cancel the common factor:

2 x - 3

= \frac{2 x + 3}{x + 1}

(3 + 3 i)^{8}

12 8^{\frac{1}{3}}

(3 a^{2} b + 2 b^{2})^{3}

(3 - 2 i) + (4 + 5 i)

- 6 \cdot 1

What is (4x^2-9)/(2x^2-x-3) ?
The solution to (4x^2-9)/(2x^2-x-3) is (2x+3)/(x+1)