What are the solutions to the equation 400-16t^2=0 ?

The solutions to the equation 400-16t^2=0 are t=5,t=-5

Find the zeros of 400-16t^2=0

The zeros of 400-16t^2=0 are t=5,t=-5

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400 - 16 t^{2} = 0

t = 5, t = - 5

Solution steps

400 - 16 t^{2} = 0

Move

400

to the right side

- 16 t^{2} = - 400

Divide both sides by

- 16

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

- \frac{4}{3} a = 18

3 x lo g_{10} (2) + x lo g_{10} (5) = 5 lo g_{10} (5) - lo g_{10} (2)

- \frac{1}{2} (1)^{2}

\frac{π}{\frac{π}{4}}

∣ x - 7 ∣ \leq 8

What are the solutions to the equation 400-16t^2=0 ?
The solutions to the equation 400-16t^2=0 are t=5,t=-5
Find the zeros of 400-16t^2=0
The zeros of 400-16t^2=0 are t=5,t=-5