What is (x^2+4x-12)/(x^2(x^2+9x+18))*6x^2 ?

The solution to (x^2+4x-12)/(x^2(x^2+9x+18))*6x^2 is (6(x-2))/(x+3)

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simplify (x^2+4x-12)/(x^2(x^2+9x+18))*6x^2

simplify

\frac{x ^{2} + 4 x - 12}{x ^{2} ( x ^{2} + 9 x + 18 )} \cdot 6 x^{2}

\frac{6 ( x - 2 )}{x + 3}

Solution steps

\frac{x ^{2} + 4 x - 12}{x ^{2} ( x ^{2} + 9 x + 18 )} \cdot 6 x^{2}

Cancel

\frac{x ^{2} + 4 x - 12}{x ^{2} ( x ^{2} + 9 x + 18 )} : \frac{x - 2}{x ^{2} ( x + 3 )}

= \frac{x - 2}{x ^{2} ( x + 3 )} \cdot 6 x^{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 2 ) \cdot 6 x ^{2}}{x ^{2} ( x + 3 )}

Cancel the common factor:

x^{2}

= \frac{( x - 2 ) \cdot 6}{x + 3}

= \frac{6 ( x - 2 )}{x + 3}

2^{- 1} + 2^{- 2}

6 (ab + a^{2}) - 5 (a^{2} - ab) + 2 (ba - a^{2})

\frac{240}{360}

1 - \frac{1}{1 - \frac{1}{1 - \frac{1}{2}}} + 2

\frac{cos ( a )}{sin ( a )}

What is (x^2+4x-12)/(x^2(x^2+9x+18))*6x^2 ?
The solution to (x^2+4x-12)/(x^2(x^2+9x+18))*6x^2 is (6(x-2))/(x+3)