What is 6(ab+a^2)-5(a^2-ab)+2(ba-a^2) ?

The solution to 6(ab+a^2)-5(a^2-ab)+2(ba-a^2) is -a^2+13ab

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simplify 6(ab+a^2)-5(a^2-ab)+2(ba-a^2)

simplify

6 (ab + a^{2}) - 5 (a^{2} - ab) + 2 (ba - a^{2})

- a^{2} + 13 ab

Solution steps

6 (ab + a^{2}) - 5 (a^{2} - ab) + 2 (ba - a^{2})

Expand

6 (ab + a^{2}) : 6 ab + 6 a^{2}

= 6 ab + 6 a^{2} - 5 (a^{2} - ab) + 2 (ba - a^{2})

Expand

- 5 (a^{2} - ab) : - 5 a^{2} + 5 ab

= 6 ab + 6 a^{2} - 5 a^{2} + 5 ab + 2 (ba - a^{2})

Expand

2 (ba - a^{2}) : 2 ab - 2 a^{2}

= 6 ab + 6 a^{2} - 5 a^{2} + 5 ab + 2 ab - 2 a^{2}

Group like terms

= 6 a^{2} - 5 a^{2} - 2 a^{2} + 6 ab + 5 ab + 2 ab

Add similar elements:

6 a^{2} - 5 a^{2} - 2 a^{2} = - a^{2}

= - a^{2} + 6 ab + 5 ab + 2 ab

Add similar elements:

6 ab + 5 ab + 2 ab = 13 ab

= - a^{2} + 13 ab

\frac{240}{360}

1 - \frac{1}{1 - \frac{1}{1 - \frac{1}{2}}} + 2

\frac{cos ( a )}{sin ( a )}

(3 x^{a + 1}) (2 x^{a}) (- x^{- 2 a})

\frac{7 x ^{2} - 25 x - 12}{7 x - 28}

What is 6(ab+a^2)-5(a^2-ab)+2(ba-a^2) ?
The solution to 6(ab+a^2)-5(a^2-ab)+2(ba-a^2) is -a^2+13ab