What is ((-2x)/(y^2))^{-4} ?

The solution to ((-2x)/(y^2))^{-4} is (y^8)/(16x^4)

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simplify ((-2x)/(y^2))^{-4}

simplify

(\frac{- 2 x}{y ^{2}})^{- 4}

\frac{y ^{8}}{16 x ^{4}}

Solution steps

(\frac{- 2 x}{y ^{2}})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{- 2 x}{y ^{2}})^{- 4} = \frac{1}{( \frac{- 2 x}{y ^{2}} ) ^{4}}

= \frac{1}{( \frac{- 2 x}{y ^{2}} ) ^{4}}

Simplify

(\frac{- 2 x}{y ^{2}})^{4} : \frac{16 x ^{4}}{y ^{8}}

= \frac{1}{\frac{16 x ^{4}}{y ^{8}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{8}}{16 x ^{4}}

2 i^{77}

\frac{2 x ^{2} - 2 x}{x ^{2} - 1}

\frac{\frac{x + 2}{x - 1}}{\frac{x + 4}{x ^{2} + 4 x - 5}}

x^{3} + 1 + 2 x^{2} + 2 x

x^{3} - 5 x^{2} + 3 x + 6

What is ((-2x)/(y^2))^{-4} ?
The solution to ((-2x)/(y^2))^{-4} is (y^8)/(16x^4)